X^2-16x+55=3

Solution for X^2-16x+55=3 equation:

X^2-16X+55=3

We move all terms to the left:

X^2-16X+55-(3)=0

We add all the numbers together, and all the variables

X^2-16X+52=0

a = 1; b = -16; c = +52;
Δ = b2-4ac
Δ = -162-4·1·52
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{3}}{2*1}=\frac{16-4\sqrt{3}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{3}}{2*1}=\frac{16+4\sqrt{3}}{2}
$